Customers arrive at a shopping mart randomly at a rate of 7 per hour.
a) Find the probability that during any 90 minutes’ period, the number of customers arriving at the shopping mart is exactly 8.
b) If a customer arrives at 11.30 am, find the probability that the next patient arrives before 11.45 am.
a
"\\lambda"=7 per hour
in 90 mins "\\lambda"=10.5 per hour
P(x)="\\frac{\\lambda^x(e^-\\lambda)}{x!}"
P(8)="\\frac{10.5^8\\cdot e^-10.5}{8!}"
P(8)=0.1009
b
For 15 mins "\\lambda"=7/4 per 15 mins
P(1)="\\frac{(7\/4)^1\\cdot e^-7\/4}{1!}"
P(1)=0.3041
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