How many possible samples of size n = 9 can be drawn from a population of size 12?
The number of possible samples which can be selected without replacement is
(Nn)=N!n!⋅(N−n)!==(129)=12!9!⋅3!==10⋅11⋅122⋅3=220.\begin{pmatrix} N \\ n \end{pmatrix}=\cfrac{N! } {n! \cdot(N-n)! }=\\ =\begin{pmatrix} 12\\ 9 \end{pmatrix}=\cfrac{12! } {9! \cdot3! }=\\ =\cfrac{10\cdot11\cdot12}{2\cdot3}=220 .(Nn)=n!⋅(N−n)!N!==(129)=9!⋅3!12!==2⋅310⋅11⋅12=220.
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