A population consist of three numbers 3,4,8.Consider all possible samples of size 2 which can be drawn with replacement from the population.Find the following population mean, population variance, population standard deviation
Samples:(3,3),(3,4),(3,8)(4,3),(4,4),(4,8)(8,3),(8,4),(8,8)μ=3+4+83=5σ2=(3−5)2+(4−5)2+(8−5)23=4.66667σ=σ2=4.66667=2.16025Samples:\\\left( 3,3 \right) ,\left( 3,4 \right) ,\left( 3,8 \right) \\\left( 4,3 \right) ,\left( 4,4 \right) ,\left( 4,8 \right) \\\left( 8,3 \right) ,\left( 8,4 \right) ,\left( 8,8 \right) \\\mu =\frac{3+4+8}{3}=5\\\sigma ^2=\frac{\left( 3-5 \right) ^2+\left( 4-5 \right) ^2+\left( 8-5 \right) ^2}{3}=4.66667\\\sigma =\sqrt{\sigma ^2}=\sqrt{4.66667}=2.16025Samples:(3,3),(3,4),(3,8)(4,3),(4,4),(4,8)(8,3),(8,4),(8,8)μ=33+4+8=5σ2=3(3−5)2+(4−5)2+(8−5)2=4.66667σ=σ2=4.66667=2.16025
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