Answer to Question #322819 in Statistics and Probability for Gian

Question

A molding machine prepares a certain kind of car spare part with a target diameter 𝜇 =

40.265 millimeters. The machine has some variability, so the standard deviation of the

diameters is 𝜎 = 0.004 millimeters. A sample of 6 spare parts is inspected each hour for

process control purposes and records are kept of the sample mean diameter. What will be

the mean and standard deviation of the numbers recorded?

Answer 1

$\mu$ =40.265

σ=0.004

The sampling distribution states

$\bar{x}$ =$\mu$

$s=\frac{\sigma}{\sqrt{n}}$

Thus

$\bar{x}$ is equal to 40.625

s=$\frac{0.004}{\sqrt{6}}$ =0.00163

$\frac{}{}$ $\frac{}{}$