Suppose the random variable X has the uniform distribution on the integers 10,11,12
......,30 Find probability that X is the prime number
There are 6 prime numbers between 10 and 30 inclusive (11, 13, 17, 19, 23, 29).
P(X=prime number)=621=27≈0.2851.P(X=prime\; number)=\frac{6}{21}=\frac{2}{7}\approx 0.2851.P(X=primenumber)=216=72≈0.2851.
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