Consider the composition of a 3-child family in which the children were born at different times but a girl is as likely as a boy at each birth.what is the probability that the oldest child and the youngest are of the same gender
P(1st and 3rd are the same gender)==P(1st boy,3rd boy)+P(1st girl,3rd girl)==12⋅12+12⋅12=0.5P\left( 1st\,\,and\,\,3rd\,\,are\,\,the\,\,same\,\,gender \right) =\\=P\left( 1st\,\,boy,3rd\,\,boy \right) +P\left( 1st\,\,girl,3rd\,\,girl \right) =\\=\frac{1}{2}\cdot \frac{1}{2}+\frac{1}{2}\cdot \frac{1}{2}=0.5P(1stand3rdarethesamegender)==P(1stboy,3rdboy)+P(1stgirl,3rdgirl)==21⋅21+21⋅21=0.5
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