Question #322424

Consider the composition of a 3-child family in which the children were born at different times but a girl is as likely as a boy at each birth.what is the probability that the oldest child and the youngest are of the same gender

Expert's answer

P(1st  and  3rd  are  the  same  gender)==P(1st  boy,3rd  boy)+P(1st  girl,3rd  girl)==12⋅12+12⋅12=0.5P\left( 1st\,\,and\,\,3rd\,\,are\,\,the\,\,same\,\,gender \right) =\\=P\left( 1st\,\,boy,3rd\,\,boy \right) +P\left( 1st\,\,girl,3rd\,\,girl \right) =\\=\frac{1}{2}\cdot \frac{1}{2}+\frac{1}{2}\cdot \frac{1}{2}=0.5


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