For a group of 20 items, sum of X = 1452, sum of x 2 = 144800 and mode = 67,
find the Karl Pearson’s coefficient of skewness and interpret the results.
"\\bar{x}=\\frac{\\sum{x_i}}{n}=\\frac{1452}{20}=72.6\\\\s=\\sqrt{\\frac{\\sum{{x_i}^2}-n\\bar{x}^2}{n}}=\\sqrt{\\frac{144800-20\\cdot 72.6^2}{20}}=44.3761\\\\K=\\frac{\\bar{x}-Mo}{s}=\\frac{72.6-67}{44.3761}=0.126194\\\\The\\,\\,distribution\\,\\,is\\,\\,positively\\,\\,skewed"
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