Question #320777

The 1500 students weight are normally distributed with a mean of 50kg with the standard deviation of S-5 lbs?

A. How many students are less than 46kg

B. How many students are heavier than 113.5lbs


1
Expert's answer
2022-03-31T06:44:32-0400

1 pound is equal to 0,4536 kilograms.

We have a normal distribution,

μ=50 kg=500.4536=110.2 lbs,σ=5 lbs=50.4536=2.27 kg.\mu=50 \textnormal{ kg}=\cfrac{50}{0.4536}=110.2 \textnormal{ lbs}, \\ \sigma=5 \textnormal{ lbs}=5\cdot0.4536=2.27\textnormal{ kg}.

Let's convert it to the standard normal distribution, z=xμσ.z=\cfrac{x-\mu}{\sigma}.



A. The probability that the student is less than 46kg:

z1=46502.27=1.76,z_1=\cfrac{46-50}{2.27}=-1.76,

P(X<360 kg)=P(Z<1.76)=0.0392P(X<360\textnormal{ kg})=P(Z<-1.76)=0.0392 ​(from z-table).

The number of such students:

0.03921500=58.859.0.0392\cdot1500=58.8\approx59.


B. The probability that the student is heavier than 113.5 lbs:

z2=113.5110.25=0.66,z_2=\cfrac{113.5-110.2}{5}=0.66,

P(X>113.5 lbs)=P(Z>0.66)=1P(Z<0.66)==10.7454=0.2546P(X>113.5\textnormal{ lbs})=P(Z>0.66)=1-P(Z<0.66)=\\ =1-0.7454=0.2546

​(from z-table).

The number of such students:

0.25461500=381.9382.0.2546\cdot1500=381.9\approx382.

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