1 pound is equal to 0,4536 kilograms.
We have a normal distribution,
μ=50 kg=0.453650=110.2 lbs,σ=5 lbs=5⋅0.4536=2.27 kg.
Let's convert it to the standard normal distribution, z=σx−μ.
A. The probability that the student is less than 46kg:
z1=2.2746−50=−1.76,
P(X<360 kg)=P(Z<−1.76)=0.0392 (from z-table).
The number of such students:
0.0392⋅1500=58.8≈59.
B. The probability that the student is heavier than 113.5 lbs:
z2=5113.5−110.2=0.66,
P(X>113.5 lbs)=P(Z>0.66)=1−P(Z<0.66)==1−0.7454=0.2546
(from z-table).
The number of such students:
0.2546⋅1500=381.9≈382.
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