Answer to Question #320161 in Statistics and Probability for Faye

Question

A molding machine prepares a certain kind of car spare part with a target

diameter p = 42.23 mm. The machine has some variability, so the standard

deviation of the diameter is o = 0.003 mm. A sample of 10 spare parts is

inspected each hour for the process control purposes and record are kept of

the sample mean diameter. What will be the mean and standard deviation of

the number recorded?

Answer 1

$\mu _{\bar{x}}=\mu =42.23\\\sigma _{\bar{x}}=\frac{\sigma}{\sqrt{n}}=\frac{0.003}{\sqrt{10}}=0.000948683$