Question #319923

Suppose a random variable x is best described by a normal distribution with μ = 60 and Find the z-score that corresponds to the value x = 63.


1
Expert's answer
2022-03-29T16:00:56-0400

z=63−60σ=3σz=\frac{63-60}{\sigma}=\frac{3}{\sigma} .


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