Answer to Question #319289 in Statistics and Probability for osama

Statistics and Probability

Question #319289

Let X follows a normal distribution with mean 40 and variance 9. Then mean of Y= (X-40)/3 is

Expert's answer

$M({\frac {X-40} 3})=M({\frac X 3}-{\frac {40} 3})={\frac 1 3}M(X)-M({\frac {40} 3})={\frac {40} 3}-{\frac {40} 3}=0$

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