Question #319233

Direction: Answer the following and illustrate each under the normal curve:


1. Compute the probability area to the left of z = -1.25.


2. Compute the probability area above z = 1.


3. Find the probability area between z = -0.25 and z = 1.5.


4. Find the 90th percentile of a normal curve.


5. Compute the upper 5% of the normal curve.

1
Expert's answer
2022-03-28T17:04:36-0400

1) P(Z<1.25)=0.10565P(Z<-1.25)=0.10565

2) P(Z>1)=0.15866P(Z>1)=0.15866




3) P(0.25<Z<1.5)=P(Z<1.5)P(Z<0.25)=0.933190.40129=0.5319P(-0.25<Z<1.5)=P(Z<1.5)-P(Z<-0.25)=0.93319-0.40129=0.5319




4) P(Z<a)=0.9    a=1.282P(Z<a)=0.9\implies a=1.282






5) The upper 5% is interval (a,+)(a,+\infty) where

P(Z>a)=0.05    a=1.645P(Z>a)=0.05\implies a=1.645


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