In a science test, the mean score is 42 and the standard deviation is 5. Assuming the scores are normally distributed, what percent of the score is greater than 47
μ=42,σ=5\mu=42,\sigma=5μ=42,σ=5
P(x>47)=1−P(x<47)P(x>47)=1-P(x<47)P(x>47)=1−P(x<47)
=1−P(Z<47−425)=1-P(Z<\frac{47-42}{5})=1−P(Z<547−42)
=1−P(Z<1.0)=1-P(Z<1.0)=1−P(Z<1.0)
=1−0.8413=1-0.8413=1−0.8413
=0.1587=0.1587=0.1587
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