Question

In a science test, the mean score is 42 and the standard deviation is 5. Assuming the scores are normally distributed, what percent of the score is greater than 47

Answer 1

$\mu=42,\sigma=5$

$P(x>47)=1-P(x<47)$

$=1-P(Z<\frac{47-42}{5})$

$=1-P(Z<1.0)$

$=1-0.8413$

$=0.1587$