Question

Let X be a random variable with the following probability distribution:

x. -3 , 6 , 9

P(X=x). 1/6 , 1/2 , 1/3

Find ug(x), where g(X)= (2X+1)^2

Answer 1

$\mu(g(X))=(-3*2+1)^2*\frac{1}{6}+(6*2+1)^2*\frac{1}{2}+(9*2+1)^2*\frac{1}{3}=209.$