A population consists of three numbers (3,4,7). Consider all possible samples of size 2 which can be drawn from the population. Find the variance of the sampling distribution of the sample means.
μ(3,4)=(3+4)/2=3.5\mu(3,4)=(3+4)/2=3.5μ(3,4)=(3+4)/2=3.5
μ(3,7)=(3+7)/2=5\mu(3,7)=(3+7)/2=5μ(3,7)=(3+7)/2=5
μ(4,7)=(4+7)/2=5.5\mu(4,7)=(4+7)/2=5.5μ(4,7)=(4+7)/2=5.5
f(3.5)=f(5)=f(5.5)=1/3
E(x)=∑fx=1/3(3.5+5+5.5)=4.7E(x)=\sum fx=1/3(3.5+5+5.5)=4.7E(x)=∑fx=1/3(3.5+5+5.5)=4.7
σ2=∑fx2−(∑fx)2=1/3(12.25+25+30.25)−22.09=0.41\sigma^2=\sum fx^2-(\sum fx)^2=1/3(12.25+25+30.25)-22.09=0.41σ2=∑fx2−(∑fx)2=1/3(12.25+25+30.25)−22.09=0.41
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