The mean weight of 20-year-old females is 126 pounds and the standard deviation is 15.7. If a sample of 25 females is selected, find the probability that the mean of the sample will be greater than 128.3 pounds. Assume that the variable is normally distributed.
We have a normal distribution, "\\mu=126, \\sigma=15.7, n=25."
Let's convert it to the standard normal distribution,
"z=\\cfrac{\\bar{x}-\\mu}{\\sigma\/\\sqrt{n}}" =
"=\\cfrac{128.3-126}{15.7\/\\sqrt{25}}=0.73,"
"P(\\bar{X}>128.3)=1-P(\\bar{X}<128.3)=\\\\\n=1-P(Z<0.73)="
"=1-0.7673=0.2327." (from z-table)
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