H 0 : μ 1 = μ 2 H 1 : μ 1 ≠ μ 2 n 1 = 9 n 2 = 8 x ˉ 1 = ∑ x i n 1 = 50.8889 x ˉ 2 = ∑ y i n 2 = 51.5 s 1 2 = ∑ ( x i − x ˉ 1 ) 2 n 1 − 1 = 2.6111 s 2 2 = ∑ ( y i − x ˉ 2 ) 2 n 2 − 1 = 8.2857 ν = ( s 1 2 n 1 + s 2 2 n 2 ) 2 1 n 1 − 1 ( s 1 2 n 1 ) 2 + 1 n 2 − 1 ( s 2 2 n 2 ) 2 = ( 2.6111 9 + 8.2857 8 ) 2 1 8 ( 2.6111 9 ) 2 + 1 8 ( 8.2857 8 ) 2 = 12.1558 ≈ 12 T = x ˉ 1 − x ˉ 2 s 1 2 n 1 + s 2 2 n 2 = 50.8889 − 51.5 2.6111 9 + 8.2857 8 = − 0.530723 P − v a l u e : P ( ∣ T ∣ > 0.5307 ) = 2 F t , 12 ( − 0.5307 ) = 2 ⋅ 0.3027 = 0.6054 H_0:\mu _1=\mu _2\\H_1:\mu _1\ne \mu _2\\\\n_1=9\\n_2=8\\\bar{x}_1=\frac{\sum{x_i}}{n_1}=50.8889\\\bar{x}_2=\frac{\sum{y_i}}{n_2}=51.5\\{s_1}^2=\frac{\sum{\left( x_i-\bar{x}_1 \right) ^2}}{n_1-1}=2.6111\\{s_2}^2=\frac{\sum{\left( y_i-\bar{x}_2 \right) ^2}}{n_2-1}=8.2857\\\nu =\frac{\left( \frac{{s_1}^2}{n_1}+\frac{{s_2}^2}{n_2} \right) ^2}{\frac{1}{n_1-1}\left( \frac{{s_1}^2}{n_1} \right) ^2+\frac{1}{n_2-1}\left( \frac{{s_2}^2}{n_2} \right) ^2}=\frac{\left( \frac{2.6111}{9}+\frac{8.2857}{8} \right) ^2}{\frac{1}{8}\left( \frac{2.6111}{9} \right) ^2+\frac{1}{8}\left( \frac{8.2857}{8} \right) ^2}=12.1558\approx 12\\T=\frac{\bar{x}_1-\bar{x}_2}{\sqrt{\frac{{s_1}^2}{n_1}+\frac{{s_2}^2}{n_2}}}=\frac{50.8889-51.5}{\sqrt{\frac{2.6111}{9}+\frac{8.2857}{8}}}=-0.530723\\P-value:\\P\left( \left| T \right|>0.5307 \right) =2F_{t,12}\left( -0.5307 \right) =2\cdot 0.3027=0.6054 H 0 : μ 1 = μ 2 H 1 : μ 1 = μ 2 n 1 = 9 n 2 = 8 x ˉ 1 = n 1 ∑ x i = 50.8889 x ˉ 2 = n 2 ∑ y i = 51.5 s 1 2 = n 1 − 1 ∑ ( x i − x ˉ 1 ) 2 = 2.6111 s 2 2 = n 2 − 1 ∑ ( y i − x ˉ 2 ) 2 = 8.2857 ν = n 1 − 1 1 ( n 1 s 1 2 ) 2 + n 2 − 1 1 ( n 2 s 2 2 ) 2 ( n 1 s 1 2 + n 2 s 2 2 ) 2 = 8 1 ( 9 2.6111 ) 2 + 8 1 ( 8 8.2857 ) 2 ( 9 2.6111 + 8 8.2857 ) 2 = 12.1558 ≈ 12 T = n 1 s 1 2 + n 2 s 2 2 x ˉ 1 − x ˉ 2 = 9 2.6111 + 8 8.2857 50.8889 − 51.5 = − 0.530723 P − v a l u e : P ( ∣ T ∣ > 0.5307 ) = 2 F t , 12 ( − 0.5307 ) = 2 ⋅ 0.3027 = 0.6054
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