Compute first 4 moments about arithmetic mean from the data .
6,5,4,7,13,5,4,3,8,5
μ=(6+5+4+7+13+5+4+3+8+5)/10=6\mu=(6+5+4+7+13+5+4+3+8+5)/10=6μ=(6+5+4+7+13+5+4+3+8+5)/10=6
First moment equal 0
Second moment
∑i(xi−μ)210=0+1+4+1+49+1+4+9+4+110=7.4\frac{\sum_i(x_i-\mu)^2}{10}=\frac{0+1+4+1+49+1+4+9+4+1}{10}=7.410∑i(xi−μ)2=100+1+4+1+49+1+4+9+4+1=7.4
Third moment
∑i(xi−μ)310=0+1+8+1+343+1+8+27+8+110=39.8\frac{\sum_i(x_i-\mu)^3}{10}=\frac{0+1+8+1+343+1+8+27+8+1}{10}=39.810∑i(xi−μ)3=100+1+8+1+343+1+8+27+8+1=39.8
Foth moment
∑i(xi−μ)4n=0+1+16+1+2401+1+16+81+16+110=253.3\frac{\sum_i(x_i-\mu)^4}{n}=\frac{0+1+16+1+2401+1+16+81+16+1}{10}=253.3n∑i(xi−μ)4=100+1+16+1+2401+1+16+81+16+1=253.3
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