A committee of 4 men and 6 women is to be selected from 7 men and 8 women .if there is a married couple among the 15 people,in how many ways the committee be selected so that the couple are automatically the committee
As the couple are automatically in the committee, we need to count the number of the ways to be selected 3 men from 6 and 5 women from 7. The order does not matter, so we count the number of combinations without repetition:
"\\begin{pmatrix} 6 \\\\ 3 \\end{pmatrix} \\cdot \\begin{pmatrix} 7 \\\\ 5 \\end{pmatrix}=\\cfrac{6!}{3!\\cdot(6-3)!}\\cdot\\cfrac{7!}{5!\\cdot(7-5)!}=\\\\\n=\\cfrac{4\\cdot5\\cdot6}{2\\cdot3}\\cdot\\cfrac{6\\cdot7}{2}=420."
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