Given that the variance is Q, determine the standard deviation in terms of Q.
a) 0.5Q
b) 2Q
c) Q
d) Q2
a) σ2=0.5Q→σ=0.5Q≈0.71Q.\sigma^2=0.5Q \to\sigma =\sqrt{0.5Q}\approx 0.71\sqrt{Q}.σ2=0.5Q→σ=0.5Q≈0.71Q.
b) σ2=2Q→σ=2Q≈1.41Q.\sigma^2=2Q \to\sigma =\sqrt{2Q}\approx 1.41\sqrt{Q}.σ2=2Q→σ=2Q≈1.41Q.
c) σ2=Q→σ=Q.\sigma^2=Q \to\sigma =\sqrt{Q}.σ2=Q→σ=Q.
d) σ2=Q2→σ=Q2=Q.\sigma^2=Q^2 \to\sigma =\sqrt{Q^2}=Q.σ2=Q2→σ=Q2=Q.
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