if two coins and a dice are thrown at once, what is the probability of getting two heads and six or one tail, one head and a three?
Assuming coins are fair, the probability of getting heads on a coin is equal to the probability of getting tails, phead=ptail=1/2. Similarly, assuming a dice is fair, the probability of getting any number on a dice is equal, px=1/6.
Probabilities of independent events that happen simultaneously should be multiplied. Hence, the probability of getting two heads and six on a dice equals
phead*phead*p6=1/2*1/2*1/6=1/24.
Probabilities of disjoint events that both can happen should be added. Hence, the probability of getting one head and one tail and a three is
(phead*ptail+ptail*phead)*p3=(1/2*1/2+1/2*1/2)*1/6=1/12.
Then the total probability is
1/24+1/12=3/24.
ANSWER: 3/24
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