Find the mean of the probability distribution of a random variable X which can take
only the values 2, 4, 5, and 9, given that P(2)=9/20, P(5)=1/20, P(5)=1/5, and
P(9)=3/10
EX=2⋅920+4⋅120+5⋅15+9⋅310=4.8EX=2\cdot \frac{9}{20}+4\cdot \frac{1}{20}+5\cdot \frac{1}{5}+9\cdot \frac{3}{10}=4.8EX=2⋅209+4⋅201+5⋅51+9⋅103=4.8
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