Find the mean of the probability distribution of a random variable X which if 𝑃(𝑋) =
𝑥+1
20
for X= 1, 2, 3, 4, and 5.
EX=∑x=15x⋅x+120=120(1⋅2+2⋅3+3⋅4+4⋅5+5⋅6)=3.5EX=\sum_{x=1}^5{x\cdot \frac{x+1}{20}}=\frac{1}{20}\left( 1\cdot 2+2\cdot 3+3\cdot 4+4\cdot 5+5\cdot 6 \right) =3.5EX=∑x=15x⋅20x+1=201(1⋅2+2⋅3+3⋅4+4⋅5+5⋅6)=3.5
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments