Question #315633

Find the mean of the probability distribution of a random variable X which if š‘ƒ(š‘‹) =




š‘„+1




20




for X= 1, 2, 3, 4, and 5.

Expert's answer

EX=āˆ‘x=15xā‹…x+120=120(1ā‹…2+2ā‹…3+3ā‹…4+4ā‹…5+5ā‹…6)=3.5EX=\sum_{x=1}^5{x\cdot \frac{x+1}{20}}=\frac{1}{20}\left( 1\cdot 2+2\cdot 3+3\cdot 4+4\cdot 5+5\cdot 6 \right) =3.5


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS