Question #315633

Find the mean of the probability distribution of a random variable X which if 𝑃(𝑋) =




𝑥+1




20




for X= 1, 2, 3, 4, and 5.

1
Expert's answer
2022-03-24T19:18:44-0400

EX=x=15xx+120=120(12+23+34+45+56)=3.5EX=\sum_{x=1}^5{x\cdot \frac{x+1}{20}}=\frac{1}{20}\left( 1\cdot 2+2\cdot 3+3\cdot 4+4\cdot 5+5\cdot 6 \right) =3.5


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