Find the mean of the probability distribution of a random variable X which if
P(X)=1/10 for X=1, 2, 3, …, 10.
μ=110(1+2+3+...+10)=5.5.\mu=\frac{1}{10}(1+2+3+...+10)=5.5.μ=101(1+2+3+...+10)=5.5.
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