Find the mean of the probability distribution of a random variable X which can take
only the values 2, 4, 5, and 9, given that P(2)=9/20, P(5)=1/20, P(5)=1/5, and
P(9)=3/10.
μ=2∗920+4∗120+5∗15+9∗310=6.8.\mu=2*\frac{9}{20}+4*\frac{1}{20}+5*\frac{1}{5}+9*\frac{3}{10}=6.8.μ=2∗209+4∗201+5∗51+9∗103=6.8.
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