Question #315630

Find the mean of the probability distribution of a random variable X which can take



only the values 3, 5, and 7, given that P(3)=7/30, P(5)= 1/3, and P(7)=13/30

Expert's answer

μ=3730+513+71330=5.4.\mu=3*\frac{7}{30}+5*\frac{1}{3}+7*\frac{13}{30}=5.4.


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