In how many ways can 6 people be seated for group photographs if there are only 4 seats?
As the order of the people does matter, we need to find the number of permutations without repetition, we choose 4 people of 6:
"P(n, r) =\\cfrac{n! } {(n-r)! } ;\\\\\nP(6,4)=\\cfrac{6!}{2!}=6\\cdot5\\cdot4\\cdot3=360."
Comments
Leave a comment