The random variable X is best described by a normal distribution with mean of 30 and standard deviation of 6. Find the z-score that corresponds to th following X values. a. X = 21 b. X = 26 c. X = 35 d. X = 42 e. X = 50
The z score formula is:
Z="\\frac{X-\\mu}{\\sigma}"
Therefore, when:
a) X=21
Z="\\frac{21-30}{6}" = -1.5
b)X=26
Z="\\frac{26-30}{6}" =-0.67
c)X=35
Z="\\frac{35-30}{6}" =0.83
d) X=42
Z="\\frac{42-30}{6}" = 2
e) X=50
Z="\\frac{50-30}{6}" =3.33
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