Consider the composition of a 3-child family in which the children were born at different times but a girl is as likely as a boy at each birth. What is the probability that the oldest child and the youngest child are of the same gender
A−1st and 3rd child of the same genderP(A)=P(1st boy,3rd boy)+P(1st girl,3rd girl)==12⋅12+12⋅12=0.5A-1st\,\,and\,\,3rd\,\,child\,\,of\,\,the\,\,same\,\,gender\\P\left( A \right) =P\left( 1st\,\,boy, 3rd\,\,boy \right) +P\left( 1st\,\,girl, 3rd\,\,girl \right) =\\=\frac{1}{2}\cdot \frac{1}{2}+\frac{1}{2}\cdot \frac{1}{2}=0.5A−1stand3rdchildofthesamegenderP(A)=P(1stboy,3rdboy)+P(1stgirl,3rdgirl)==21⋅21+21⋅21=0.5
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