The average time it takes a group of college students to a certain examination is 57.3 minutes . The standard deviation is 9 minutes . Assume that the variable is normally distributed. What is the Probability that a randomly selected college student will complete the examination in less than 54 minutes
"P\\left( X\\leqslant 54 \\right) =P\\left( \\frac{X-57.3}{\\sigma}\\leqslant \\frac{54-57.3}{9} \\right) =P\\left( Z\\leqslant -0.3667 \\right) =\\varPhi \\left( -0.3667 \\right) =0.3569"
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