Answer to Question #314976 in Statistics and Probability for Angela

Question

The average monthly income of employees in a certain company is P28,000 with a

standard deviation of P9,000. Below which income do we find the lowest 5% of the

nincomps?

Answer 1

$P(Z<z)=0.05 \to z=-1.645. \;\;\frac{x-28000}{9000}=-1.645 \to x=28000-1.645*9000=13195.$

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