The average monthly income of employees in a certain company is P28,000 with a
standard deviation of P9,000. Below which income do we find the lowest 5% of the
nincomps?
P(Z<z)=0.05→z=−1.645. x−280009000=−1.645→x=28000−1.645∗9000=13195.P(Z<z)=0.05 \to z=-1.645. \;\;\frac{x-28000}{9000}=-1.645 \to x=28000-1.645*9000=13195.P(Z<z)=0.05→z=−1.645.9000x−28000=−1.645→x=28000−1.645∗9000=13195.
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