Question #314257



Jepoy has one 100-peso bill, two 200-peso bills, and five 500-peso bills in his wallet. He wants to randomly pick one bill. Let X be the random variable of choosing one bill from his wallet.



Questions:


1. Construct the probability distribution table of X. [2 points]


2. Compute for the mean of X, denoted as E(X). [2 points]


3. Interpret the mean of X. [1 point]


4. Compute for the variance of X, denoted as V(X). [5 points]


5. Compute for the standard deviation of X, denoted as SD(X). [2 points]


Interpret the standard deviation of X. [1 point

1
Expert's answer
2022-03-19T04:09:34-0400

1:P(X=100)=18=0.125P(X=200)=28=0.25P(X=500)=58=0.625x100200500P(X=x)0.1250.250.6252:EX=1000.125+2000.25+5000.625=3753:Ataverage375pesobillistaken4:EX2=10020.125+20020.25+50020.625=167500V(X)=EX2(EX)2=1675003752=268755:SD(X)=V(X)=26875=163.9366:Ataveragetherangeofbillamountis±164peso1:\\P\left( X=100 \right) =\frac{1}{8}=0.125\\P\left( X=200 \right) =\frac{2}{8}=0.25\\P\left( X=500 \right) =\frac{5}{8}=0.625\\\begin{matrix} x& 100& 200& 500\\ P\left( X=x \right)& 0.125& 0.25& 0.625\\\end{matrix}\\2:\\EX=100\cdot 0.125+200\cdot 0.25+500\cdot 0.625=375\\3:\\At\,\,average\,\,375-peso\,\,bill\,\,is\,\,taken\\4:\\EX^2=100^2\cdot 0.125+200^2\cdot 0.25+500^2\cdot 0.625=167500\\V\left( X \right) =EX^2-\left( EX \right) ^2=167500-375^2=26875\\5:\\SD\left( X \right) =\sqrt{V\left( X \right)}=\sqrt{26875}=163.936\\6:\\At\,\,average\,\,the\,\,range\,\,of\,\,bill\,\,amount\,\,is\,\,\pm 164 peso


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