Answer to Question #313763 in Statistics and Probability for John

Question

P ( 0 < z < 2.0 )

Answer 1

P(0<Z<2)= P(Z<2)-P(Z<0)

From the standard normal table, we find that:

P(Z<2)=0.9773

P(Z<0)=0.5

Therefore:

P(0<Z<2)= 0.9773-0.5

=0.4773

Answer:0.4773