Suppose a random selected family has 3 children. Define X to be the number of boys in the family, X = 0,1,2, and 3. Write the sample space, construct a probability distribution in table form, and make histogram.
Sample space: X = {0,1,2,3}
X ~ Bin(3, 0.5)
P(X=0)=(30)∗(12)3=18P(X=0)={3 \choose 0}*({\frac 1 2})^3={\frac 1 8}P(X=0)=(03)∗(21)3=81
P(X=1)=(31)∗(12)3=38P(X=1)={3 \choose 1}*({\frac 1 2})^3={\frac 3 8}P(X=1)=(13)∗(21)3=83
P(X=0)=(32)∗(12)3=38P(X=0)={3 \choose 2}*({\frac 1 2})^3={\frac 3 8}P(X=0)=(23)∗(21)3=83
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