Question

A Wendy's manager performed a study to determine a probability distribution for the number of people, X, waiting in a line during lunch. The results were as follows. Find and interpret the probability that 10 or more people are waiting in line for lunch?

Answer 1

*The probability distribution is missing and is as shown

The probability that 10 or more people are waiting in line

$P(X \ge10)=P(10)+P(11)+P(12)$

$P(X\ge10)=0.019+0.004+0.006$

$P(X\ge10)=0.029$

The probability is $0.029$ which is low indicating that it's unusual and less probable to find 10 or more people waiting in line