Box A and Box B both contain the numbers 1,2,3, and 4. Construct the probability mass function and draw the histogram of the sum when one number from each box is taken at a time, with replacement
Let X be a random variable representing the sum of the numbers, then X = {2,3,4,5,6,7,8}
P(X=2)=116P(X=2)={\frac 1 {16}}P(X=2)=161
P(X=3)=216=18P(X=3)={\frac 2 {16}}={\frac 1 8}P(X=3)=162=81
P(X=4)=316P(X=4)={\frac 3 {16}}P(X=4)=163
P(X=5)=416=14P(X=5)={\frac 4 {16}}={\frac 1 4}P(X=5)=164=41
P(X=6)=316P(X=6)={\frac 3 {16}}P(X=6)=163
P(X=7)=216=18P(X=7)={\frac 2 {16}}={\frac 1 8}P(X=7)=162=81
P(X=8)=116P(X=8)={\frac 1 {16}}P(X=8)=161
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