a. Using the provided information below,
x=33.2, x2=131.67, y=30.78 , y2=116.52 , xy=119.8 , and n=10
i. Find the sample correlation coefficient r
ii. Find the co-efficient of determination
i.
r=n∑xy−∑x∑y[n∑x2−(∑x)2][[n∑y2−(∑y)2]r=\frac{n∑xy-∑x∑y}{\sqrt{[n∑x^2-(∑x)^2][[n∑y^2-(∑y)^2]}}r=[n∑x2−(∑x)2][[n∑y2−(∑y)2]n∑xy−∑x∑y
=10(119.8)−33.2(30.78)[10(131.667)−33.22][10(116.52)−30.782=\frac{10(119.8)-33.2(30.78)}{\sqrt{[10(131.667)-33.2^2][10(116.52)-30.78^2}}=[10(131.667)−33.22][10(116.52)−30.78210(119.8)−33.2(30.78)
=1198−1024.884(214.46)(217.7916)=\frac{1198-1024.884}{\sqrt{(214.46)(217.7916)}}=(214.46)(217.7916)1198−1024.884
=173.11646707.58654=\frac{173.116}{\sqrt{46707.58654}}=46707.58654173.116
=173.116216.1194=\frac{173.116}{216.1194}=216.1194173.116
=0.801=0.801=0.801
ii. r2=0.6416r^2=0.6416r2=0.6416
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