On a final examination in mathematics, the mean was 76 and the standard deviation was 5. Determine the
standard score of a student who received a score of 88 assuming the scores are normally distributed. (
Solution
Population mean "\\mu = 76"
Standard deviation "\\sigma=5"
"X=88"
"Z=\\dfrac{X-\\mu}{\\sigma}=\\dfrac{88-76}{5}"
"Z=2.4"
From normal distribution tables
P(Z of 2.4)"=0.99180"
or
"99.18\\%"
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