Question #312161

There are 150 students in a class. The distribution if their marks in a mathematics test are as follows

Class                                                   frequency

0-9                                                      3

10-19                                                  10

20-29                                                  17

30-39                                                  x

40-49                                                  35

50-59                                                  y

60-69                                                  18

70-79                                                  10

80-89                                                  5

90-99                                                  2

Required

i)       The value of x given that the median mark is 44.357            (2marks)

ii)     The value of y given that the modal is 43.0                          (2marks)

iii)   Draw an ogive of the data in (a) above                                 (3 marks)


1
Expert's answer
2022-03-17T06:34:21-0400



i. median =44.357=L+((N2pcf)f)i=44.357=L+(\frac{(\frac{N}{2}-pcf)}{f})i

=40+((75(30x)35)10=40+(\frac{(75-(30-x)}{35})10

=39.5+((45x)35)10=39.5+(\frac{(45-x)}{35})10

4.357=((45x)35)104.357=(\frac{(45-x)}{35})10

0.4357=(45x)350.4357=\frac{(45-x)}{35}

15.2495=45x15.2495=45-x

x=29.75x=29.75

ii. Mode =43.0=40+(7(7+35y))10=43.0=40+(\frac{7}{(7+35-y)})10

40+(7(42y))1040+(\frac{7}{(42-y)})10

3=(7(42y))103=(\frac{7}{(42-y)})10

0.3=7(42y)0.3=\frac{7}{(42-y)}

42y=70.3=23.3342-y=\frac{7}{0.3}=23.33

y=422.33=18.67y=42-2.33=18.67

iii.





Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS