Question #312143

Marketing estimates that a new instrument for the analysis of soil samples will be very successful, moderately successful, or unsuccessful, which is probabilities 0.3, 0.6, and 0.1, respectively. The yearly revenue associated with a very successful, moderately successful, or unsuccessful is $10 million, $5 million, and $1 million, respectively. Let the random variable X denote the yearly revenue of the product. Determine:




a) the mass function of X;




b) the mean of X; and




c) the variance of X.

1
Expert's answer
2022-03-16T17:05:16-0400

Solution

Let X denote the yearly revenue of the product.


(a) The mass function of X

The probability mass function of X is as shown in the diagram below.





(b) The mean of X


Mean μ=XP(X)\mu=\sum XP(X)


μ=10(0.3)+5(0.6)+1(0.1)\mu=10(0.3)+5(0.6)+1(0.1)


μ=6.1\mu=6.1


(c) The variance of X


σ2=X2.P(X)μ\sigma^2=\sum X^2.P(X)-\mu


σ2=[102(0.3)+52(0.6)+12(0.1)]6.12\sigma^2=[10^2(0.3)+5^2(0.6)+1^2(0.1)]-6.1^2


σ2=45.137.21\sigma^2=45.1-37.21


σ2=7.89\sigma^2=7.89



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