The probabilities that a traffic inspector will discover violations of the Traffic Code in Davao City are given in the following table.
Number of Violations (X)
Probability P(X)
0.41
1
2
3
0.22
0.17
4
5
0.13
0.05
0.02
a. Solve for the mean and variance. b. Interpret the mean and the variance of the problem.
Solution
Mean
"\\mu_x=\\sum XP(X)"
"\\mu_x=[0(0.41)+1(0.22)+2(0.17)+3(0.13)+4(0.05)+5(0.02)]"
"\\mu_x=1.25"
Variance
"\\sigma^2=\\sum X^2.P(X)-\\mu^2"
"\\sigma^2=[0(0.41)+1^2(0.22)+2^2(0.17)+3^2(0.13)+4^2(0.05)+5^2(0.02)]-1.25^2"
"\\sigma^2=3.37-1.5625"
"\\sigma^2=1.8075"
The mean is small (1.25) and closer to the lower numbers (0 1 and 2) due to their larger probability compared to the other numbers (3 4 and 5)
The variance is relatively small (1.8075) indicating that the results are close to each other.
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