Question

On a Physicians Licensure Exam with a population mean of 83 and standard deviation of 8. Jenny scores 4 points below the mean, Jeffrey had a score of x=84 and Jolly had a z-score of 0.30. Place these three students in order from the lowest to highest.

Answer 1

$\mu=83, \ \ \sigma =8.$

Jenny's score: $x_1=\mu-4=83-4=79.$

Jeffrrey's score: $x_2=84.$

Jolly's z-score: $z_3=\frac{x_3-\mu}{\sigma},$

Jolly's score:

$x_3=z_3\sigma+\mu=0.3\cdot8+83=85.4.$

The students in order from the lowest to highest: Jenny, Jeffrrey, Jolly.