A random sample of 60 students is chosen from a large population with an average diastolic blood pressure of 100 and a standard deviation of 36. What is the probability that the mean diastolic blood pressure of these 60 students is less than 110?
P(Xˉ<110)=P(Z<110−1003660)=P(Z<2.15)=0.9842.P(\bar X<110)=P(Z<\frac{110-100}{\frac{36}{\sqrt{60}}})=P(Z<2.15)=0.9842.P(Xˉ<110)=P(Z<6036110−100)=P(Z<2.15)=0.9842.
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