An electronic company in Laguna manufactures resistors that have a mean resistance of 120 ohms and a standard deviation of 13 ohms. Find the probability that a random sample of 40 resistors will an average resistance greater than 114 ohms.
"P(\\bar X>114)=P(Z>\\frac{114-120}{\\frac{13}{\\sqrt{40}}})=P(Z>-2.92)=1-P(Z<-2.92)=0.9982."
Comments
Leave a comment