An electronic company in Laguna manufactures resistors that have a mean resistance of 120 ohms and a standard deviation of 13 ohms. Find the probability that a random sample of 40 resistors will an average resistance greater than 114 ohms.
P(Xˉ>114)=P(Z>114−1201340)=P(Z>−2.92)=1−P(Z<−2.92)=0.9982.P(\bar X>114)=P(Z>\frac{114-120}{\frac{13}{\sqrt{40}}})=P(Z>-2.92)=1-P(Z<-2.92)=0.9982.P(Xˉ>114)=P(Z>4013114−120)=P(Z>−2.92)=1−P(Z<−2.92)=0.9982.
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