Solution
1.
For a population;
mean μ=N∑Xi
Variance σ2=N∑(Xi−μ)2
Standard deviation σ=N∑(Xi−μ)2
mean μ=71+9+2+12+8+7+1
μ=5.71
Variance
Xi11278912∑Xi−μ−4.71−4.71−3.711.292.293.296.29(Xi−μ)222.1822.1813.761.665.2410.8239.56115.40
σ2=7115.4=16.49
Standard deviation
σ=7115.4=4.06
2.
Population size N=7
Sample size n=6
Possible number of samples
=C76=(67)=7 Samples
no.1234567Sample1,1,2,7,8,91,1,2,7,8,121,1,2,7,9,121,1,2,8,9,121,1,7,8,9,121,2,7,8,9,121,2,7,8,9,12Samplemean4.675.175.335.506.336.506.50
Sampling distribution of the sample means
Mean4.675.175.335.506.336.50Probability717171717172
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