Question #310215

Experiment: Tossing two coins. Random variable 𝑋 = number of heads a) List all possible sample space. b) Find the random variable values. c) Find the probabilities for the random variable values.



1
Expert's answer
2022-03-15T07:48:50-0400

a) Let's use the letters H and T for “head” and “tail” respectively. The sample space:

S={TT,HT,TH,HH}.S = \begin{Bmatrix} TT, HT, TH, HH\end{Bmatrix}.


b) In the case of TT (i.e we got two tails) X = 0; for HT and TH (first head, second tail or vice versa) X = 1 and for HH (both heads) X = 2.


c) The probability that we get head p=12,p = \frac{1}{2}, that we get tail q=1p=112=12.q = 1-p=1-\frac{1}{2}=\frac{1}{2}.

The result of both tossings are independent events, for each sample point:

P(TT)=P(T)P(T)=qq=1212=14;P(TH)=P(T)P(H)=qp=1212=14;P(HT)=P(T)P(H)=pq=1212=14;P(HH)=P(T)P(H)=pp=1212=14.P(TT)=P(T)\cdot P(T)=q\cdot q =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(TH)=P(T)\cdot P(H)=q\cdot p =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(HT)=P(T)\cdot P(H)=p\cdot q =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(HH)=P(T)\cdot P(H)=p\cdot p =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}.

The probabilities for the random variable values:

P(X=0)=P(TT)=14;P(X=1)=P(TH)+P(HT)=14+14=12;P(X=2)=P(HH)=14.P(X=0)=P(TT)=\frac{1}{4};\\ P(X=1)=P(TH)+P(HT)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2};\\ P(X=2)=P(HH)=\frac{1}{4}.



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