Question #310215

Experiment: Tossing two coins. Random variable 𝑋 = number of heads a) List all possible sample space. b) Find the random variable values. c) Find the probabilities for the random variable values.



Expert's answer

a) Let's use the letters H and T for β€œhead” and β€œtail” respectively. The sample space:

S={TT,HT,TH,HH}.S = \begin{Bmatrix} TT, HT, TH, HH\end{Bmatrix}.


b) In the case of TT (i.e we got two tails) X = 0; for HT and TH (first head, second tail or vice versa) X = 1 and for HH (both heads) X = 2.


c) The probability that we get head p=12,p = \frac{1}{2}, that we get tail q=1βˆ’p=1βˆ’12=12.q = 1-p=1-\frac{1}{2}=\frac{1}{2}.

The result of both tossings are independent events, for each sample point:

P(TT)=P(T)β‹…P(T)=qβ‹…q=12β‹…12=14;P(TH)=P(T)β‹…P(H)=qβ‹…p=12β‹…12=14;P(HT)=P(T)β‹…P(H)=pβ‹…q=12β‹…12=14;P(HH)=P(T)β‹…P(H)=pβ‹…p=12β‹…12=14.P(TT)=P(T)\cdot P(T)=q\cdot q =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(TH)=P(T)\cdot P(H)=q\cdot p =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(HT)=P(T)\cdot P(H)=p\cdot q =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4};\\ P(HH)=P(T)\cdot P(H)=p\cdot p =\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}.

The probabilities for the random variable values:

P(X=0)=P(TT)=14;P(X=1)=P(TH)+P(HT)=14+14=12;P(X=2)=P(HH)=14.P(X=0)=P(TT)=\frac{1}{4};\\ P(X=1)=P(TH)+P(HT)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2};\\ P(X=2)=P(HH)=\frac{1}{4}.



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