a) Let's use the letters H and T for “head” and “tail” respectively. The sample space:
S={TT,HT,TH,HH}.
b) In the case of TT (i.e we got two tails) X = 0; for HT and TH (first head, second tail or vice versa) X = 1 and for HH (both heads) X = 2.
c) The probability that we get head p=21, that we get tail q=1−p=1−21=21.
The result of both tossings are independent events, for each sample point:
P(TT)=P(T)⋅P(T)=q⋅q=21⋅21=41;P(TH)=P(T)⋅P(H)=q⋅p=21⋅21=41;P(HT)=P(T)⋅P(H)=p⋅q=21⋅21=41;P(HH)=P(T)⋅P(H)=p⋅p=21⋅21=41.
The probabilities for the random variable values:
P(X=0)=P(TT)=41;P(X=1)=P(TH)+P(HT)=41+41=21;P(X=2)=P(HH)=41.
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