Question #310208

The officers of the Mathematics Club are planning to sell 280 tickets to be raffled during


the school’s foundation day. One ticket will win ₱5,000, two tickets will win ₱3,000, three


tickets will win ₱2,000 and the other tickets will win nothing. If you will buy one ticket,


what will be your expected value and variance of his gain?

1
Expert's answer
2022-03-15T18:28:41-0400

Let X be the value of the gain. Then

P(X=5000)=1280P(X=3000)=2280P(X=2000)=3280EX=50001280+30002280+20003280=60.7143EX2=500021280+300022280+200023280=196429DX=EX2(EX)2=19642960.71432=192742P\left( X=5000 \right) =\frac{1}{280}\\P\left( X=3000 \right) =\frac{2}{280}\\P\left( X=2000 \right) =\frac{3}{280}\\EX=5000\cdot \frac{1}{280}+3000\cdot \frac{2}{280}+2000\cdot \frac{3}{280}=60.7143\\EX^2=5000^2\cdot \frac{1}{280}+3000^2\cdot \frac{2}{280}+2000^2\cdot \frac{3}{280}=196429\\DX=EX^2-\left( EX \right) ^2=196429-60.7143^2=192742\\

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