If the amount of cosmic radiation to which a person is exposed while flying by jet across the United States is a random variable having the normal distribution with mean as
4.35 mrem and standard deviation as 0.59 mrem. Find the probabilities that the amount of cosmic radiation to which a person is exposed on such a flight is:
a) Between 4.00 mrem to 5.00 mrem,
b) At least 5.50 mrem,
c) No more than 4.5 mrem.
we define the following
a) p(4<x<5), given mean =4.35 and standard deviation=0.59, we use z calculations as below
z(4) = (4 - 4.35) / (0.59) = -0.59
z(5) = (5- 4.35) / (0.59) = 1.10
hence p(4<x<5) = p(-0.59 < z <1.10), using normal tables we obtain
(0.86433 - 0.27760) = 0.58673
b) we define p(x≥5.5), using z calculations , we have
z(5.5) = (5.5 - 4.35) / (0.59) = 1.95
hence p(x≥5.5) = 1 - p(z<1.95) = (1 - 0.97441) = 0.02559
c) we define p(x≤4.5), using z calculations, we have
z(4.5) = (4.5 - 4.35) / (0.59) = 0.25
hence p(x≤4.5) = p(z<0.25), using normal tables we have
= 0.59871
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