Question

The average monthly salary for a newly hired employeeat a bank is 20,000.If the hiring salary at this bank is normally distributed with a standard deviation of 2,800 ,what is the probability that a newly hired employee randomly selected from a list of receives a monthly salary which is less than 16,000

Answer 1

$\mu=20000,\sigma=2800, Z=(x-μ)/σ$

$P(x<16000)=P(Z<(16000-20000)/2800)$

$=P(Z<-1.43)$ From z distribution table

$=0.0764$