given the mean μ 124 and standard deviation is σ = 3. find the z-value that corresponds to a score X=118. then find and graph the proportion of the are greater than the computer z-value
given the mean "\u03bc= 124"
standard deviation is "\u03c3 = 3"
(a)
"Z=\\dfrac{X-\\mu}{\\sigma}=\\dfrac{118-124}{3}"
"Z=-2.0"
(b) P value for "Z(-2.0)=0.02275"
"=2.275\\%"
The proportion greater than the Z value (Z=-2.0)"=(100-2.275)\\% = 97.725\\%"
The proportion is shaded as shown below
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