given the mean μ 124 and standard deviation is σ = 3. find the z-value that corresponds to a score X=118. then find and graph the proportion of the are greater than the computer z-value
given the mean μ=124μ= 124μ=124
standard deviation is σ=3σ = 3σ=3
(a)
Z=X−μσ=118−1243Z=\dfrac{X-\mu}{\sigma}=\dfrac{118-124}{3}Z=σX−μ=3118−124
Z=−2.0Z=-2.0Z=−2.0
(b) P value for Z(−2.0)=0.02275Z(-2.0)=0.02275Z(−2.0)=0.02275
=2.275%=2.275\%=2.275%
The proportion greater than the Z value (Z=-2.0)=(100−2.275)%=97.725%=(100-2.275)\% = 97.725\%=(100−2.275)%=97.725%
The proportion is shaded as shown below
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